Question

Find the absolute maximum and absolute minimum values of f(x)= e^x -x on interval [-1,1]

Answer 1

f(x)= e^x -x
take the derivative:
e^x-1
set equal to zero
0 = e^x-1
solve for x

Answer 2

thats how far i got, i cannot figure out what to do when i get e^x=1

Answer 3

this one is a trick of knowing zero powers,
any number raised to a power of zero = 1

for example
45^0 = 1
1^0 = 1
makes sense?

Answer 4

yes so is it just one?

Answer 5

wow, openstudy is messed up today, sorry i didn't see your respsonse

Answer 6

e^x=1
so,
e^0=1, because any number raised to a zero power =1, so,
x=0