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Find the absolute maximum and absolute minimum values of f(x)= e^x -x on interval [-1,1]
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f(x)= e^x -x take the derivative: e^x-1 set equal to zero 0 = e^x-1 solve for x
thats how far i got, i cannot figure out what to do when i get e^x=1
this one is a trick of knowing zero powers, any number raised to a power of zero = 1 for example 45^0 = 1 1^0 = 1 makes sense?
yes so is it just one?
wow, openstudy is messed up today, sorry i didn't see your respsonse
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e^x=1 so, e^0=1, because any number raised to a zero power =1, so, x=0
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