Question

write an algorithm to calculate the sum of the digits of a three-digit number ?
ANY HELP

Answer 1

class program
{
public static void main(String args[])
{
int num = 405;
int h = num/100;
int rem = num%100;
int t=rem/10;
int u=rem%10;
int sum= h+t+u;

System.out.println("Hundred's digit =" + h);
System.out.println("Ten's digit =" + t);
System.out.println("Unit's digit =" + u);
System.out.println("Sum of digits =" + sum);

}

}

Answer 2

Nice try the which I feel is correct!

Answer 3

public class b1
{

public int retNum(int num)
double num1 = num/100;
double num2 = num%100;
double num3 = num2/10;
double num4 = num2%10;
int val = (int) (num1 +num3 +num4);
return val;
}

Answer 4

The I called the function using the following:

Answer 5

class callfunc1
{
public static void main(string args [])
{
b1 b10 = new b1()
System.out.println("The sum is:" + b10.retNum(num);
}
}

Answer 6

ok thanx for you 2.. i got it