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3 over 4 x + 5 over 8 = 4x
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\[\large \frac{ 3 }{ 4 }x +\frac{ 5 }{ 8 } = 4x\] this?
Yes!
Okay. Get x on one side and the constant on the other. \[\large -3\frac{ 1 }{ 4 } x= -\frac{ 5 }{ 8 }\] Multiply by reciprocal to get rid of the fraction on x. \[\large x = -\frac{ 5 }{ 8 } \times -\frac{ 8 }{ 13 }\] \[\large x = \frac{ 5 }{ 13 }\]
ok. but i'm kind of confused
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