Question

1
-x^2+2+3=0 what are the solutions?
2

Answer 1

the easiest way to visualize this is multiply both sides by -1 to get the lead coefficient positive. then you will have
\[x^2-2x-3\]
then this is easily factored

Answer 2

ax^2+bx+c=0 --> x1=(-b+(b^2-4ac)^1/2)/2a and x2=(-b-(b^2-4ac)^1/2)/2a

Answer 3

x^2-3x+x-3=0
x(x-3)+x-3=0
(x-3)(x+1)=0
x=-1 and x=3

Answer 4

@mandik1974

Answer 5

;) thanks