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Mathematics 19 Online
OpenStudy (anonymous):

algebra 2?!?!

OpenStudy (anonymous):

OpenStudy (anonymous):

OPTION C) IS RIGHT ...IF U WANT EXPLANATION I WILL GIVE .

OpenStudy (skullpatrol):

@vinurules how about giving a hint first?

OpenStudy (jack1):

numerator: (3/x) +(2/x+2) = (5x+6)/(x^2+2x) denominator: (3/(x+2)) - (2/x) = (x-4)/(x^2 +2x) divide by fraction = multiply by reciprocal so: \[ \huge \frac {\frac {(5x+6)}{(x^2+2x)}}{\frac {(x-4)}{(x^2 +2x)} } ~~~=~~ \large\frac {(5x+6)} {(x^2+2x)} \times\frac {(x^2 +2x)}{(x-4)} \] \[ \large = \frac {5x + 6x}{x - 4} \]

OpenStudy (jack1):

sorry, typo = 5x + 6 / x - 4 ..... not 5x +6x / x - 4

OpenStudy (anonymous):

@skullpatrol--next time sure i will ..one of my friend explained me how to write here .i will follow that

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