Question

Find the diffrential equation
y"-8y=0

Answer 1

what have you tried so far?

Answer 2

@TuringTest the net is not good, he may be kicked out, not intendedly.

Answer 3

y''=8y
y'=8(1/2)y^2+C
y=8(1/2)(1/3)y^3+C
y=(4/3)y^3+C
suppose C=0
y=0
y-(4/3)y^3=0
y(1-(4/3)y^2)=0
1=(4/3)y^2
+-sqrt(3/4)=y
has 3 roots