Question

I really need help on this graph. Its in a picture

Answer 1

Thanks

Answer 2

List the atom out,
C (left) you have 1, now C (right) 1, \(\checkmark \)
S (left) 2 (from \(S_2\)) , now S (right) 2 \(\checkmark \)
O (left) 6(from \(3O_2\), now O (right) 6 (2 from \(CO_2 \) and 4 from \(S_2O_4\)) \(\checkmark\)
So, no need to add any number in the front.
That's the process you have to put in the table, I use "left" to indicate the reactant and "right" to indicate the product