Question

solve by the elimination method
3x=42+2y
5x=4-4y

Answer 1

all the examples my teacher gave did not involve a x on the other side

Answer 2

3x-2y=42......EQ 1
5x+4y=4.........EQ 2
mutiply eq 1 by 2
now it becomes
6x -4y =84
5x+4y=4
now eliminate 4y , it would be cancel
6x=84
5x=4
adding them
11x=88
x=88\11
x=8
now put the value of x in eq 2
5(2)+4y=4
4y=4-10
4y=-6
y=-6\4
y=-3\2
so the solution set is { ( 8,-3\2) }
this is the correct answer

Answer 3

I know but im also working on other problems because this work is timed i just wanted some input but thank you @Loser66