Question

The perimeter of a rectangle is 68 feet and its width is 8/9 times its length. Find the dimensions of the rectangle

Answer 1

Perimeter of rectangle = 2(length) + 2(width)
so given P = 68 and L = 8/9W
then 68 = 2(8/9 W) + 2W
68 = 16/9 W + 18/9 W
68 = 34/9 W
W = 18
then plug back into P = 2L + 2W
so 68 = 2L + 2(18)
then find L
therefore W = ___ and L = ___

Answer 2

Thank you so much!!

Answer 3

you're welcome ;)