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Mathematics 10 Online
OpenStudy (anonymous):

Kk so I am asked to find θ for 0° ≤ θ < 360° I am given the fact that sin θ = -0.3319 So after inverse sine(-0.3319) my angle turns out to be -19.38 (i took four significant digits to graph). I know that this angle lies in the first quadrant. But this is as far as I can go by my self. Should I have added the -19.38 + 180 = 160.6?? Please help /:

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