Question

maximum of -x^2+8x

Answer 1

Okay so take the derivative of -x^2+8x
which is -2x+8
now set it equal to zero because the maximum is where the slope equals 0
So -2x+8=0
so x= 4 is where the maximum is
When x = 4 then the y coordinate equals 16
So. The maximum is (4,16)