Question

Condense . express as a single logarithm and if possible ,simplify
logb^8x+6(logb^x-logb^y)

Answer 1

What do you get?

Try using these rules
http://www.mathwords.com/l/logarithm_rules.htm

Answer 2

i don't know how to start

Answer 3

Is it \[\large \log b^{8x}+6(\log b^x-\log b^y)\]

Answer 4

right

Answer 5

Distribute 6 first

Answer 6

Give me more hint plzz

Answer 7

Use
\[\log a^b + \log a^d = \log (a^ba^d)=\log(a^{b+d})\]
\[\log a^b -\log a ^d=\log(\frac{a^b}{a^d})=\log(a^{b-d})\]