Question

if f(x)=(x|x|)/(1+x^2) then f-1(x) is equal to.........?

Answer 1

i think you have to work in cases
if \(x>0\) then this is
\[f(x)=\frac{x^2}{1+x^2}\] whereas if \(x<0\) it is
\[f(x)=\frac{-x^2}{1+x^2}\] so you will have to find the inverse twice