Question

Please help?
write the equations for tangent with the period=1/3pi, phase shift=-1/4pi, vertical shift= -5

y=tan(3theta+3/4pi)-5
y=tan(1/3theta+3/4pi)+5
y=tan(1/3theta-3/4pi)+5
y=tan(3theta-3/4pi)-5

Answer 1

For F(t) = A(Bt – C) + D, where f(t) is one of the basic trig functions, we have:

A: amplitude is A
B: period is (2π)/|B|
C: phase shift is C/B
D: vertical shift is D


Identify what you have.

Answer 2

y = tan ( 1/3 pi + 1/4 pi ) - 5

Answer 3

Oh i made an error

Answer 4

-1/4 x 3/1 = phase shift
= -3/4

Answer 5

Wow, thanks!!

Answer 6

y = Atan(Bt – C) + D
y = 1 tan ( 1/3 pi - (-3/4) + (-5)

Answer 7

y = tan (1/3pi + 3/4) - 5

Answer 8

My trig is somewhat rusty :S

Answer 9

Thanks for all the help! I think I understand it now ^^

Answer 10

and I forgot the pi symbol afterwards again lol
y = tan ( 1/3 pi + 3/4 pi ) - 5
Yeah, no problem.

Answer 11

If you need more help in understanding this, I know it may be long but it helps
http://www.purplemath.com/modules/grphtrig.htm

Answer 12

Okay, thanks ^^ My text didnt go into much detail so I this'll make more sense.

Answer 13

This one is a bit more detailed and easier. http://www.regentsprep.org/regents/math/algtrig/ATT7/indexATT7.htm