Question

evaluate the indefinite integral. (1/sqrtx)dx

Answer 1

think of how to represent \[\sqrt x\]in the form\[x^a\]

Answer 2

x^1/2

Answer 3

so\[{1\over\sqrt x}=?\]

Answer 4

typo\[\frac1{x^a}=x^{-a}\]

Answer 5

so 1/x^1/2=x^-1/2

Answer 6

right :)
now what is\[\int x^ndx\]?

Answer 7

would it be 2x^1/2

Answer 8

+c