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Find the equation for the tangent line to the graph of y=f(x):
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Slope intercept form: y=mx+b Point slope form: y-y1=m(x-x1) which one does your answer need to be in?
I am confused on how to find the slope part, I got y0=f(1)=e , f'(x)=2e^(2x-1)
so m=f'(1)?
Plug in what you have so far into one of the equation forms
so, 2e^(2x-1)=2e(1)=2e
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So you're done. You don't have to solve. Good job.
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