Question

The parametric equations for a line L1 are as follows:
x = −5−6t
y = 5+9t
z = −2+3t

Let L2 be the line parallel to L1 and passing through the point (4, −3, −3). Find the point P on L2 whose x-coordinate is −12.

Answer 1

Have you considered:

x = 3−6t
y = -3+9t
z = −3+3t

??

Now what?