Question

help please. algebra word problem.
the length of a rectangle is 3 inches more than the width. the area is 18 square inches. find the dimensions.

Answer 1

You are given.
A= 18
A = LW
L = 3 + W
Plug it in.

18 = (3+W)(W)
w^2 + 3w - 18 = 0
(w+6)(w-3) = 0
w=3
(since you cannot have a negative width)

A = LW
18 = L(3)
6 = L

Answer 2

thank you!