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maximum y value on the graph f(x)=-x^2+6x=4
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Is that positive or negative 4?
positive 4 and its meant to be -x^2+6x+4. sorry
I hope you can see it.
f(4)=12 ?
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Yes
When the function is positive, it's minimum.
The parabola is opens downward in this function f(x)=-x^2+6x+4
The constant is 4, which couldn't make the 6x, so I would use quadratic formula to get the values of x.
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Approximate your answer, so you don't spin your head. Jk. It's alright to do it according to my Math101 prof.
thankyou!
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