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help. how does i^18 = -1?
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i^18 = (i^2)^9 = (-1)^9 = -1
thank you! :)
Also: \[\LARGE i^1=\sqrt{-1}\] \[\LARGE i^2=-1\] \[\LARGE i^4=\sqrt{1}\] \[\LARGE i^3=-i\]
And as we see, 18 is a factor of 2, so it would be the i^2
thanks for the help
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