Question

0.5e ^-0.08x

Answer 1

how may i help you

Answer 2

0.5e ^-0.08x, how do I get a primitive function out of it?
Thank you inadvance.

Answer 3

do you know how to integrate it ?

Answer 4

\[\int e^{ax}dx\]\[=\frac1ae^{ax}+C\]

Answer 5

Can you plug \(a=-0.08\) into that? :)

Answer 6

I feel so hopeless in these new formulas...Okey, then according to Kennylau, this will give me 1/0.08 * 0.5e^0.08x + C

Answer 7

um yes

Answer 8

But where should I mulpiply things? The answer should be -6.25e^0.08x

Answer 9

Well let's write it out first and you'll get it:\[-\frac1{0.08}\times0.5\times e^{-0.08x}+c\]

Answer 10

oooh! I just multiply the numbersl leaving the e^n , plus the constant sign
Thank you!

Answer 11

no problem :)