Question

(z+6)(z-6)

Answer 1

difference of perfect squares.
see how the MIDDLE TERM is CANCLED or equal zero?

it would just be
\[z^2-36\]

Answer 2

thanks

Answer 3

As any time you have \[(a+b)(a-b)~~~i t~~would~~be~~~(a^2-b^2)\]

Answer 4

Anytime!

Answer 5

(x+5)(x+3)

Answer 6

\[(x+3)(x+5)~~->~~~[x \times (x+5)] + [3 \times (x+5)]~~->~~~[x^2+5x]+[3x+15]\]\[add~~~like~~~terms,~~~~~~x^2+8x+15\]

Answer 7

Next time post one question per thread please.

Answer 8

k thanks

Answer 9

Anytime!