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Which of the following is a solution of x2+4x=-15
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\[you~~~meant~~~~~~~~ x^2+4x=-15\]
ummmm
No I didn't mean that, what I had typed is what the question was.
see
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wait wait for it
the third 1
Sorry my connection snapped right when I wanted to posted it, \[\frac{-b±\sqrt{b^2-4ac}}{2a}\]
a=1 b=4 c=15 I added 15 to both sides to set it equal zero. \[x^2+4x\color{red}{+15}=-15\color{red}{+15}\] \[x^2+4x\color{red}{+15}=0\]
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Can you do your questions using quadratic formula?
I got it thank you
\[\huge\color{blue}{x=\frac{±\sqrt {4^2-4(1)(15)}}{2(1)}}\ \]
Anytime!
Plug in a=1, b=4, c=15 remember that \[\sqrt{-1}=i\]
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