Jeff can win the game if he rolls 11 on the two number cubes. If he rolls an even sum, however, he will lose his next turn.
What is the probability that he will win the game?__
What is the probability that he will lose his next turn?

Question

Jeff can win the game if he rolls 11 on the two number cubes. If he rolls an even sum, however, he will lose his next turn.
What is the probability that he will win the game?__
What is the probability that he will lose his next turn?

anonymous · Answer

He can only win if he gets a sum of 11, that is possible only with two possible scenarios.
first cube - 5
second cube - 6
or 
first cube - 6
second cube - 5

so probability will be = 2/36 i.e, 1/18

for the second, its very simple. The probability of rolling an even sum is - 18/36, i.e 1/2

anonymous · Answer

Thanks "fr34k"! Your answers were correct!

dumbcow · Answer

here is breakdown of probabilities of rolling a sum with 2 die

sum       prob
2             1/36
3            2/36
4           3/36
5            4/36
6            5/36
7            6/36
8             5/36
9            4/36
10           3/36
11            2/36
12            1/36

anonymous · Answer

Thanks! :)