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Mathematics 22 Online
OpenStudy (anonymous):

What is the solution of the equation?

OpenStudy (charlotte123):

Where is the equation? xD

OpenStudy (therealmeeeee):

lol were is it at X_X

OpenStudy (anonymous):

lol sorry \[3\sqrt[5]{(x+2)^3}+3=27\]

OpenStudy (therealmeeeee):

(x^3/2)^2/3 = 27^2/3 x = 3^2 x = 9

OpenStudy (therealmeeeee):

(x^3/2)^2/3 = 27^2/3 x = 3^2 x = 9

OpenStudy (therealmeeeee):

its 9

OpenStudy (anonymous):

Thank you so much :)

OpenStudy (therealmeeeee):

give me a medal

OpenStudy (therealmeeeee):

ty

OpenStudy (anonymous):

I did

OpenStudy (anonymous):

You're welcome

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