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OpenStudy (anonymous):
What is the solution of the equation?
sqrt(2x+13)-5=x
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OpenStudy (anonymous):
\[\sqrt{2x+13}-5=x\]
OpenStudy (solomonzelman):
\[\sqrt{2x+13}-5=x\]\[\sqrt{2x+13}=x+5~~~~~~~~squ are~~~both~~sides,\]\[2x+13=x^2+10x+25~~~~~~~~Can~~you~~do~~ i t~~now?\]
OpenStudy (anonymous):
Yes,thank you :)
OpenStudy (solomonzelman):
Anytime!
OpenStudy (anonymous):
I thought i could finish it,but im confused so can you help me?
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OpenStudy (solomonzelman):
\[x^2+10x+25-2x^2-13=0\]
OpenStudy (solomonzelman):
\[-x^2+10x+12=0~~~~~~->~~~~~~~~x^2-10x-12=0\]
OpenStudy (solomonzelman):
Which methods do you know?
Quadratic formula
Completing the square
Factoring
OpenStudy (solomonzelman):
All of them?
OpenStudy (anonymous):
i know all of them but mainly quadratic formula
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OpenStudy (solomonzelman):
Sorry, the connection snapped
OpenStudy (solomonzelman):
\[\huge\color{blue}{\frac{-(-10)±\sqrt{(-10)^2-4 \times 1 \times (-12)}}{2(1)}=x}\]
OpenStudy (solomonzelman):
\[\huge\color{blue}{\frac{+10±\sqrt{100-(-48)}}{2}=x}\]
\[\huge\color{blue}{\frac{+10±\sqrt{148)}}{2}=x}\]
\[\huge\color{blue}{\frac{+10±4\sqrt{37)}}{2}=x}\]
\[\huge\color{blue}{+5±2\sqrt{37}=x}\]
OpenStudy (solomonzelman):
Clear?
OpenStudy (anonymous):
yes very lol thank you so much
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