Solve the system below and identify the shape of the graph of the equation.

x^2+y^2+2x+2y=0
x^2+y^2+4x+6y+12=0

Question

Solve the system below and identify the shape of the graph of the equation.

x^2+y^2+2x+2y=0
x^2+y^2+4x+6y+12=0

shamil98 · Answer

I was doing this one the other day..
solving it algebraically was such a pain ..

shamil98 · Answer

They are both circles.

anonymous · Answer

oh no :(

shamil98 · Answer

In the end I resorted to wolfram, mostly cause I was not able to solve the system algebraically ... lol

anonymous · Answer

do you know how to do any of the math? my teacher will give me a 0 if i dont show any work so i just need something to write down :p

shamil98 · Answer

I've tried substitution..
You could try elimination

shamil98 · Answer

Nvm, elimination won't work either.. hm

anonymous · Answer

yeah i just tried that one right now and didnt get anywhere

shamil98 · Answer

The solutions are (-2,-2) and (-1.2, -2.4) 
but I have no idea how to get there lol.

anonymous · Answer

hm... do you know of any other methods to try?

shamil98 · Answer

No, time to call in for the more experienced people @dan815

anonymous · Answer

hopefully we can figure something out :o

shamil98 · Answer

mhm

anonymous · Answer

dan815 · Answer

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