A hot bowl of soup cools according to Newton's law of cooling. Its temperature (in degrees Fahrenheit) at time t is given by the function T(t) = 68 + 144e^-0.04t , where t is expressed in minutes. At what time will the soup reach 200F? How do I solve this?
T(t) = 68 + 144e^-0.04t ---> So all of those t's in the equation are expressed in minutes right? Or is it just the one in the beginning? O_o
It's a function char -_-
Well excuse me Mr. I steal yer Peach Juice =.=
I think I'm supposed to set it to equal 200. but I solved that and got 0.21 which is not an answer choice..
I want an explanation not an answer.
There's an explanation in there ya peanut ლ(́◉◞౪◟◉‵ლ)
Oh nvm I got it. its 2.175 or 2.18 so 2.18 minutes
When solving i made an error..
T(t) = 68 + 144e^-0.04t 200 = 68 + 144e^-0.04t 132/144 = e^-0.04t 0.91666666666 = e^-0.04t ln 0.91666666666 / -0.04 = t 2.17528 = t
you were of no use.
huehuehuehue
You set T(t) = 200 So your new function would be ~ 200 = 68 + 144e^−0.04t Then ya subtract 68 from both sides ~ Getting 132=144e^−0.04t You are solving for t like any other equation, so you want t on one side and the value on the other side ~ Then ya divide both sides by 144 ~
Dude Q_Q
You cut me off Q_Q
</3
Yeah, Ik that, apparently your supposed to USE THE EXACT VALUE for 132/144 i put 0.917 i guess rounding was a bad idea o-o
the exact value is 0.91666666666
Peanut head T_T
#mathlogic
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I SOLVED IT ALL BY MESELF
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