Question

three forces with magnitudes 100, 50, and 80 pounds, act on an object an angles of 50, 160, and -20 degrees respectively

Answer 1

Net force on object is dictated by sum of horizontal and vertical components
\[F = <F_x, F_y>\]
\[F_x = 100\cos(50)+50\cos(160)+80\cos(-20)\]
\[F_y = 100\sin(50)+50\sin(160)+80\sin(-20)\]

Answer 2

thank you so much! that makes a lot of sense! thanks again :)

Answer 3

yw