find the value of x round to the nearest degree
|dw:1386043061704:dw|
You can use simple trigonometric ratios to solve this. Did you try this?
i did but i didnt get the right answer
tell me what you did so I can tell u where you made the mistake
i did sin. but since there was no degree i did sin11=x over 20
|dw:1386043942126:dw| Thatz where you made the mistake. sine ratio is defined as \[\frac{ opposite side }{ hypotaneuse}\] according to the figure I have drawn here it is \[sinA = \frac{ BC }{ AC } = \frac{ a }{ b }\]
In your problem x is the angle. So you have to write trigonometric ratios for the angle. You cant write trig ratios for sides
can you understand what Im telling?
no
can u write sine,cos ratios for the triangle I have drawn?
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