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How to solve for x? 5 = log_3 (x^2 + 18)
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\[5 = \log_3 (x^2 + 18) \] let x^2 + 18=a so \[5 = log_3 a \] Does this help?
Not really , my knowledge with logarithms is little... Dumb in this area, you could say.
log_a x = N A^n = x so.. log_3 a = 5 3^5 = a ?
\[\log_3(a) = 5\]\[Log_ab=c~~~~~~~->~~~~~~a^c=b~~~~~so,~~~~YES,~~you~~got~~it!\]
Awesome! and the rest is algebra. 243 = x^2 + 18 x^2 - 225 (x+15)(x-15) x = 15, -15,
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243 = x^2 + 18 243 -18= x^2 and the answer is there CORRECT! 225=x^2 x=± 15
thanks.
Anytime!
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