A hot bowl of soup cools according to Newton's law of cooling, what is the initial temperature?
The function where t is time (in minutes ) is
T(t) = 68 + 144e^-.04t

I just need to confirm my first step.
The first step is to set t=0
for the initial temperature right?

Question

A hot bowl of soup cools according to Newton's law of cooling, what is the initial temperature?
The function where t is time (in minutes ) is
T(t) = 68 + 144e^-.04t

I just need to confirm my first step.
The first step is to set t=0
for the initial temperature right?

shamil98 · Answer

T(0) = 68 + 144e^-0.4(0)
T(0) = 68 + 144
T(0) = 212