In a dihybrid cross between RrTt and RRtt, what are the genotype and phenotype ratios of the offspring, assuming R and T are dominant? R codes for round seed, while r codes for wrinkled seed. T codes for tall height, while t codes for short height. (Show your Punnett Square)
Well you can say the genotypes of the following offspring are: RT, rt, Rt, Rt. From there, you can make your punnett square utilising these genotypes in which you can determined the phenotypes as well.
thanks for that, so i did the punnett square, im stuck with the phenotype
i got the ratio to be 1:1:1:1
hi kene..do u still need help or u got the ans?
yes!!! lol
yes what? yes u got d ans or yes u need help..lol:P
yes i need help pleaseeee
:) thanks
okay sure...so can u tell me d gametes of both the parents? can u show me how u drew d punnet?
how can i show u what u drew? lol
|dw:1386050015533:dw| did u get this?
i got this lol, im pretty lost so if im wrong im not surprised
i send you a picture of what i did
yep u r right...its just that i wrote Rt only once..while u wrote it 4 times...actually u need not write it 4 times....so eventually u get the genotypic and phenotypic ratio as 1:1:1:1
really? so i would only write it once?
if the ratio is 1:1:1:1- is that the same as the phenotype ?
yep....u write the phenotype of every gentoype then u will find out it comes to 1:1:1:1
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can u complete this?
oh i see!!
Red-green colorblindness is an X-linked recessive mutation. A colorblind female is crossed with a normal male. What are the parental genotypes? Diagram the F1 results from this cross. (show punnett square). Diagram the F2 results. (show the punnett square).
whoops i wrote wrong..i meant phenotypic ratio is !:1
so pheno is 1:1? and geno is 1:1:1:1??
yep..:)
ok thankssss
happy 2 help:D
can you help me with one more?
yes sure....
can u tell me d genotype of the parents?
Xc Xc XCY ?
yep..u r absolutely write...its just that u dont need to write XCY...U Can write it as XY
So now show me d punnet...actually u know wat...u seem good at this...:)
lol i dont think so
but thanks
yep...believe me...i have helped a lot of people wid punnets....u seem good at it...
can u draw it how i drew earlier...use d draw tool below...
i have trouble with the F1 and F2 punnets
ill help u out..dont worry wid dat...ok ill guide u a lil...i will draw d punnet u fill in the squares ok?
ok
|dw:1386051399325:dw|
XXc Yxc
absolutely right..:) so can u tell me d phenotype of them?
im lost haha
so this is where im confused at, the punnet i just filled out that is for f1? and what do i do for F2 bc thats the offspring right?
okay np...see they have given colour blindness is recessive...so for a female to have colourblindness both the X should be xcxc correct? while for a man..there is only 1 X in his genotype..right? so if that 1 X is xc then he has colourblindness...ok?
ok
so now the boy with xcY would have colorblindness..rite?
and d girl Xxc would be normal....ok? with me so far?
yes because the man has the colournlindness
cool...now in humans u lnow that u need a man and a women to get offsprings....and u have got both in the F1 cross...so take both of them find gametes and draw a punnet like we did earlier...
ok
so all clear? hope this helped.. and i see dat u r new to this site so i would suggest u to take a look at d code of conduct...:D
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