Question

Find the slope of the tangent line to the graph y = x^-3 at the point (0.5, 8).

I did:
y' = -3x^2
y' = -3(0.5)^2 = -0.75

But it's wrong. Can someone help?

Answer 1

I just saw what I did wrong! the exponent!!

Answer 2

I figured it out :) thanks!!

Answer 3

oop should be

\[y' = \frac{-3}{x^4}\]