A circle has a diameter with endpoints (-8, 2) and (-2, 6).

What is the equation of the circle?

r^2 = (x - 3)^2 + (y + 4)^2
r^2 = (x - 5)^2 + (y + 4)^2
r^2 = (x + 5)^2 + (y - 4)^2
r^2 = (x + 3)^2 + (y - 4)^2

Question

A circle has a diameter with endpoints (-8, 2) and (-2, 6).

What is the equation of the circle?


r^2 = (x - 3)^2 + (y + 4)^2
r^2 = (x - 5)^2 + (y + 4)^2
r^2 = (x + 5)^2 + (y - 4)^2
r^2 = (x + 3)^2 + (y - 4)^2

anonymous · Answer

Middle of -8 and -2 is -5
Middle of 2 and 6 is 4
So, middle of circle is (-5 , 4)
( x - (-5))^2 + (y - 4)^2
(x + 5)^2 + (y - 4)^2