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Mathematics 20 Online
OpenStudy (anonymous):

d

OpenStudy (skullpatrol):

y varies directly as the square of x $$\Huge y=kx^2$$

OpenStudy (skullpatrol):

Now use the given information: When x = 5, y = 5 to solve for k. Then find y when x = 10.

OpenStudy (skullpatrol):

@Mercedes00312 are you still there?

OpenStudy (skullpatrol):

What did you get for k?

OpenStudy (anonymous):

5=25k ?

OpenStudy (skullpatrol):

Yes, now solve for k.

OpenStudy (anonymous):

i dont know howwww

OpenStudy (skullpatrol):

use the idea of balance...whatever you do to one side of the equation you must do the same thing to the other

OpenStudy (skullpatrol):

here divide both sides by 25 to get the k alone on one side

OpenStudy (anonymous):

5/25 = k

OpenStudy (skullpatrol):

Yes, now simplify please

OpenStudy (anonymous):

1/5 = k

OpenStudy (skullpatrol):

Correct, now what is the equation with this constant.

OpenStudy (skullpatrol):

replace k with 1/5

OpenStudy (anonymous):

1/5 * 25 = 5 which isnt an answer

OpenStudy (skullpatrol):

Only k gets replaced in y = k x^2

OpenStudy (skullpatrol):

$$\Huge y=\frac{1}{5}x^2$$

OpenStudy (skullpatrol):

Now answer the question "Find y when x = 10" with this equation.

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