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y varies directly as the square of x $$\Huge y=kx^2$$
Now use the given information: When x = 5, y = 5 to solve for k. Then find y when x = 10.
@Mercedes00312 are you still there?
What did you get for k?
5=25k ?
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Yes, now solve for k.
i dont know howwww
use the idea of balance...whatever you do to one side of the equation you must do the same thing to the other
here divide both sides by 25 to get the k alone on one side
5/25 = k
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Yes, now simplify please
1/5 = k
Correct, now what is the equation with this constant.
replace k with 1/5
1/5 * 25 = 5 which isnt an answer
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Only k gets replaced in y = k x^2
$$\Huge y=\frac{1}{5}x^2$$
Now answer the question "Find y when x = 10" with this equation.
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