Ask your own question, for FREE!
English 7 Online
OpenStudy (anonymous):

Can someone please help me with Chemistry? I understand it, but I'm stuck on such a small part. I am doing "Limiting Reactant". I am homeschooled and would call my teacher for help, but I can't until at least 4 pm and I need help right now. The problem I am solving right now is: How many grams of sodium oxide can be produced when 55.3 g Na react with 64.3 g O2? Unbalanced equation: Na + O2 → Na2O Show, or explain, all of your work along with the final answer. Again, I am not asking for you to give me the answer. I want you to help me through the question step by step.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
VERNEISH: Two objects are moving along separate linear paths where each path is described by position, d, and time, t.
23 minutes ago 1 Reply 0 Medals
Arriyanalol: i need help
1 day ago 7 Replies 1 Medal
Arriyanalol: CONGRATS to me
1 day ago 8 Replies 2 Medals
Maci: what are the best stock apps for people who want to start investing?
4 days ago 3 Replies 2 Medals
Twaylor: genuienly how do i get better self control i keep watcing youtube and theres this
1 week ago 3 Replies 0 Medals
IzzyCookie: |dw:1792074056138:dw| Uhm, I don't know where to ask this, but I'm in college welding at my community college, and I need help learning vertical welding for
2 days ago 9 Replies 1 Medal
Legomaster346: What colleges are good that are near Arab Alabama?
1 week ago 5 Replies 0 Medals
Maci: what is your thoughts on qc reaching 10years lmk who the ogs
1 week ago 9 Replies 1 Medal
thehearken: not sure if this is considered spam, im sorry if it is, but does anyone have tips
1 week ago 2 Replies 1 Medal
Arriyanalol: i need help
1 week ago 6 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!