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Given the triangle below, what is sec ∡B?
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The attachment includes the possible answers and the triangle
You've got the right choice as far as I can tell. sec = hyp / adjacent the adjacent side is \[\sqrt{33}\]
\[\frac{ 7 }{ \sqrt{33} } * \frac{ \sqrt{33} }{ \sqrt{33} }\]
yeah, that's what i did
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but i looked the question up and people were getting different answers
so now im unsure
B and C are definitely wrong cause that's sin and csc A is either tangent or cotangent
oh my god did you just call me baby and lol ok
thanks for the help.
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