Question

What is 64x^3-1=0

Answer 1

Use the Difference of Cubes equation, that is (a^3-b^3) = (a-b)(a^2+ab+b^2) with a = 4x and b = 1

So:

(64x^3 - 1) = (4x - 1)(16x^2 + 4x + 1) = 0

So x = 1/4, (1/8)(-1 +/- i*sqrt(3))

Answer 2

do u get it

Answer 3

64x3+1=0
2. Use sum of cubes formula:
a3+b3=(a+b)(a2−ab+b2)
3.
(4x)3+(1)3
a=4x
and
b=1,
4.apply formula
=(4x+1)(16x2−4x+1)

Answer 4

@Bud575