Question

need help factoring x^2+6xy+9y^2-1

Answer 1

x2+6xy+9y2−1

Since both terms are perfect 2th roots, find the values a=(x+3y) and b=1.

(((x+3y))2−(1)2)

The binomial can be factored using the difference of squares formula, because both terms are perfect squares. The difference of squares formula is a2−b2=(a−b)(a+b) where a=(x+3y) and b=1.

((x+3y)−1)((x+3y)+1)

Simplify inside each of the factors.