Help please !!!!!!!:) ****

A container ship traveled to Guam and back. It took one hour longer to go there than it did to come back. The average speed on the trip was 20km/h. The average speed on the way back was 25km/h. How many hours did the trip there take?
Show work or explain.

Thank You!!! XD

Question

Help please !!!!!!!:) ****



A container ship traveled to Guam and back. It took one hour longer to go there than it did to come back. The average speed on the trip  was 20km/h. The average speed on the way back was 25km/h. How many hours did the trip there take?
Show work or explain.

Thank You!!! XD 
<3

raden · Answer

the distance to go = distance to come back
d1 = d2

we knowed that the formula for distance (d) = speed(s) * time(t)
therefore, take an equation :

d1 = d2
s1 (t+1) = s2 t
(given s1 = 20 km/h and s2 = 25 km/h)

thus
s1 (t+1) = s2 t
20(t + 1) = 25t

solve fot t = ?

raden · Answer

got it ?