Question

How do I solve

cube root of 2 to the sixth power, to the x power

Answer 1

i cant understand it
does it really say
\[\left(\sqrt[3]{2^6}\right)^x\]?

Answer 2

one thing is for sure
\[\sqrt[3]{2^6}=2^2=4\] after that i guess you have \(4^x\)

Answer 3

Sorry I'm not good with computers. But yeah that's what I meant