Question

Solve for n
-10+log3(n+3)=-10

Answer 1

n=-8/3
-10+log3(n+3)=-10
log3(n+3)=0
log3(n+3)=log1 .....(log1=0)
By comparing, 3(n+1)=1
n=(1/3)-3= -8/3

Answer 2

I disagree with the above comment, though I could be wrong. I got n=-2
10+log3(n+3)=-10
log3(n+3)=0
log((n+3)^3)=0 <-- this step is because of the exponential log property
(n+3)^3=1
n=-2
However, I could be wrong.

Answer 3

The property is actually like this
a(logn)= log(n^a)
also log(ab)=loga+logb