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An archer releases an arrow from a shoulder height of 1.39 m. When the arrow hits the target 18 m away, it hits point A. When the target is removed, the arrow lands 45 m away. Find the maximum height of the arrow along its parabolic path. HELP PLEASE I HAVE NO IDEA ive got everything else figured out I just need this
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i can help u do u want me too help u
Yes please
the parabola is defined by the equation: y = f(x) = ax² + bx + c ...where a, b, and c are constant coefficients to be determined. You are given three points: f(0) = 1.39 f(18) = h ... (height of point A) ... I suspect there's a figure you're not showing us f(45) = 0
do this help
Yea I believe I can do it now thanks (:
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yup np:)
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