Question

1. |y + 4| < 1
a. -5 < y < -3
b. -3 < y< 5
c. -4 < y < 1
d. 1 < y < 4

2. |2t| - 5 = 7
a. t = 1 or -1
b. t = 6 or -6
c. t = 10 or -10
d. t = 12 or -12

3. |2x| >= 14
a. x >= -7
b. x <= -7
c. x <= -7 and x >= -7

Answer 1

You want to isolate the coefficient and leave it on the left side alone, then divide it to just leave the variable. Then add a negative sign to make another solution. Ex: I 2x+5I >5 and 2x + 5 > -5. When you're dividing or multiplying by a negative you flip the sign.