Question

heeeelllppp?!!

Answer 1

Feel free to take everything to the left hand side and find the common denominator.

Answer 2

i'm sorry it's kind of hard to read but is it no solution then?

Answer 3

\[\frac5{x^2-4}+\frac2x=\frac2{x-2}\]\[\frac5{x^2-4}+\frac2x-\frac2{x-2}=0\]\[\frac{x-8}{(x-2) x (x+2)}=0\]\[x-8=0\]\[x=8\]