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help me solve the system y = x2 - 5 -3x + y = -7
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2x-5=-7+3x > x=2 . y=-1
understand?
-3x + x^2 - 5 = -7 -3x + x^2 + 2 = 0 x^2 - 3x + 2 = 0 ( x - 2 ) ( x -1 ) = 0 this is what i got
but u dont need to do ^2 you can solve it without that..
you need to take the y=.... and put him in the sec equ and then solve it
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and them u get the x and after that u take the x and put him in one of the two equ and that it u find the y.
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