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\[x ^{2} + y ^{2} = 4\] \[y ^{2}- x = 4 \]
no
How about this solve for y^2 in the 2nd equation: y^2= x+4 use that definition of y in the first equation \[ x^2 + y^2 = 4\\ x^2 + x+4 = 4\] can you finish ?
yeah i think so
\[x ^{2} + x =0\] then factor to \[x(x+1)\]
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yes, so x=0 or x= -1 then solve for the correspond y values
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