Question

Simplify the expression?
tan(sin^-1(x))

Answer 1

first, change tan and sin^-1
\[\tan =\frac{ \sin }{ \cos }\]
and sin^-1 = \[\frac{ 1 }{ \sin }\]

Answer 2

so, you can rewrite them like this:
\[\frac{ \sin }{ \cos } \left( \frac{ 1 }{ \sin } (x)\right)\]

Answer 3

sin^-1x is arcsin(x), it doesn't equal 1/sinx.

Answer 4

i hope this will help you..