Question

A rectangle has an area of 14 square centimeters. Its length is five cm greater than its width. Find the dimensions.
A. 2 and 7
B. 4 and 9
C. 6 and 8
D. 7 and 7

Answer 1

first determine the area formula of a rectangle

Answer 2

A = LW

and it says that Area is 14cm, so that makes it

14 = LW

the length is 5 cm greater than its width. this means we need to modify length in terms of width

14 = (W+5) W

Answer 3

so is the with 14 times 5?

Answer 4

no

Answer 5

oh... :/

Answer 6

then whats the width?

Answer 7

2

Answer 8

laughing out loud

Answer 9

ooh..so 2 times 14?

Answer 10

14 = (W+5) W

distribute then complete the square

6.25 + 14 = W^2 + 5W + 6.25

20.25 = (W+2.5)^2

obtain W by obtaining the square root of both sides of the equation

sqrt (20.25) = sqrt[(W + 2.5)^2]

4.5 = W + 2.5

solve for W by adding -2.5 on both sides of the equation

4.5 - 2.5 = W + 2.5 + (-2.5)

2 = W

Answer 11

so the area is 28?...

Answer 12

check:

A = L W

14 = (W+5) W

14 = (2+5) 2

14 = (7) 2

14 = 14
true

Answer 13

NO.

read the problem
it begins with "A rectangle has an area of 14 square centimeters. "

so the area of the rectangle is 14 cm

Answer 14

oooh so we need to find the length and width?

Answer 15

YEAH!

Answer 16

laughing out loud

Answer 17

LOL ok i kinda get it now then

Answer 18

so if the width is 2 then whats the lenght?

Answer 19

it says the length is 5 cm greater than the width
so if width is 2 then length will be 2+5

Answer 20

oooh 7! so the width is 2 nd the lenght is 7! omg im so dumb ahahaha thnx amor te lo agradesco

Answer 21

de nada